Question
Answer
$$x+3+y^2-3xy+12=-3xy+y^2+x+15$$
Explanation
| $$ \begin{aligned}x+3+y^2-3xy+12& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-3xy+y^2+x+15\end{aligned} $$ | |
| ① | Combine like terms: $$ x+ \color{blue}{3} +y^2-3xy+ \color{blue}{12} = -3xy+y^2+x+ \color{blue}{15} $$ |
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