Question
Answer
$$(x+2y-2)(x-5y-8)=x^2-3xy-10y^2-10x-6y+16$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x+2y-2)(x-5y-8)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^2-3xy-10y^2-10x-6y+16\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x+2y-2}\right) $ by each term in $ \left( x-5y-8\right) $. $$ \left( \color{blue}{x+2y-2}\right) \cdot \left( x-5y-8\right) = x^2-5xy-8x+2xy-10y^2-16y-2x+10y+16 $$ |
| ② | Combine like terms: $$ x^2 \color{blue}{-5xy} \color{red}{-8x} + \color{blue}{2xy} -10y^2 \color{green}{-16y} \color{red}{-2x} + \color{green}{10y} +16 = \\ = x^2 \color{blue}{-3xy} -10y^2 \color{red}{-10x} \color{green}{-6y} +16 $$ |
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