Question
Answer
$$(x+2)(x-3)(x-3)=x^3-4x^2-3x+18$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x+2)(x-3)(x-3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(x^2-3x+2x-6)(x-3) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}(x^2-x-6)(x-3) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}x^3-3x^2-x^2+3x-6x+18 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}x^3-4x^2-3x+18\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x+2}\right) $ by each term in $ \left( x-3\right) $. $$ \left( \color{blue}{x+2}\right) \cdot \left( x-3\right) = x^2-3x+2x-6 $$ |
| ② | Combine like terms: $$ x^2 \color{blue}{-3x} + \color{blue}{2x} -6 = x^2 \color{blue}{-x} -6 $$ |
| ③ | Multiply each term of $ \left( \color{blue}{x^2-x-6}\right) $ by each term in $ \left( x-3\right) $. $$ \left( \color{blue}{x^2-x-6}\right) \cdot \left( x-3\right) = x^3-3x^2-x^2+3x-6x+18 $$ |
| ④ | Combine like terms: $$ x^3 \color{blue}{-3x^2} \color{blue}{-x^2} + \color{red}{3x} \color{red}{-6x} +18 = x^3 \color{blue}{-4x^2} \color{red}{-3x} +18 $$ |
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