Question
Answer
$$(x-6)(x-8)(x-10)=x^3-24x^2+188x-480$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x-6)(x-8)(x-10)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(x^2-8x-6x+48)(x-10) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}(x^2-14x+48)(x-10) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}x^3-10x^2-14x^2+140x+48x-480 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}x^3-24x^2+188x-480\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x-6}\right) $ by each term in $ \left( x-8\right) $. $$ \left( \color{blue}{x-6}\right) \cdot \left( x-8\right) = x^2-8x-6x+48 $$ |
| ② | Combine like terms: $$ x^2 \color{blue}{-8x} \color{blue}{-6x} +48 = x^2 \color{blue}{-14x} +48 $$ |
| ③ | Multiply each term of $ \left( \color{blue}{x^2-14x+48}\right) $ by each term in $ \left( x-10\right) $. $$ \left( \color{blue}{x^2-14x+48}\right) \cdot \left( x-10\right) = x^3-10x^2-14x^2+140x+48x-480 $$ |
| ④ | Combine like terms: $$ x^3 \color{blue}{-10x^2} \color{blue}{-14x^2} + \color{red}{140x} + \color{red}{48x} -480 = x^3 \color{blue}{-24x^2} + \color{red}{188x} -480 $$ |
This page was created using
Simplify polynomials calculator