Question
Answer
$$(x-6)(x^2-2x+4)=x^3-8x^2+16x-24$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x-6)(x^2-2x+4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^3-2x^2+4x-6x^2+12x-24 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^3-8x^2+16x-24\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x-6}\right) $ by each term in $ \left( x^2-2x+4\right) $. $$ \left( \color{blue}{x-6}\right) \cdot \left( x^2-2x+4\right) = x^3-2x^2+4x-6x^2+12x-24 $$ |
| ② | Combine like terms: $$ x^3 \color{blue}{-2x^2} + \color{red}{4x} \color{blue}{-6x^2} + \color{red}{12x} -24 = x^3 \color{blue}{-8x^2} + \color{red}{16x} -24 $$ |
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