Question
Answer
$$(x-6)(3x+2)=3x^2-16x-12$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x-6)(3x+2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3x^2+2x-18x-12 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}3x^2-16x-12\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x-6}\right) $ by each term in $ \left( 3x+2\right) $. $$ \left( \color{blue}{x-6}\right) \cdot \left( 3x+2\right) = 3x^2+2x-18x-12 $$ |
| ② | Combine like terms: $$ 3x^2+ \color{blue}{2x} \color{blue}{-18x} -12 = 3x^2 \color{blue}{-16x} -12 $$ |
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