Question
Answer
$$(x-5)(4x+11)=4x^2-9x-55$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x-5)(4x+11)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4x^2+11x-20x-55 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4x^2-9x-55\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x-5}\right) $ by each term in $ \left( 4x+11\right) $. $$ \left( \color{blue}{x-5}\right) \cdot \left( 4x+11\right) = 4x^2+11x-20x-55 $$ |
| ② | Combine like terms: $$ 4x^2+ \color{blue}{11x} \color{blue}{-20x} -55 = 4x^2 \color{blue}{-9x} -55 $$ |
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