Question
Answer
$$x-4+(3x+5)(x-4)=3x^2-6x-24$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}x-4+(3x+5)(x-4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x-4+3x^2-12x+5x-20 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x-4+3x^2-7x-20 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}3x^2-6x-24\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3x+5}\right) $ by each term in $ \left( x-4\right) $. $$ \left( \color{blue}{3x+5}\right) \cdot \left( x-4\right) = 3x^2-12x+5x-20 $$ |
| ② | Combine like terms: $$ 3x^2 \color{blue}{-12x} + \color{blue}{5x} -20 = 3x^2 \color{blue}{-7x} -20 $$ |
| ③ | Combine like terms: $$ \color{blue}{x} \color{red}{-4} +3x^2 \color{blue}{-7x} \color{red}{-20} = 3x^2 \color{blue}{-6x} \color{red}{-24} $$ |
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