Tap the blue circles to see an explanation.
| $$ \begin{aligned}x-3(x+2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x-(3x+6) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x-3x-6 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-2x-6\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3} $ by $ \left( x+2\right) $ $$ \color{blue}{3} \cdot \left( x+2\right) = 3x+6 $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left( 3x+6 \right) = -3x-6 $$ |
| ③ | Combine like terms: $$ \color{blue}{x} \color{blue}{-3x} -6 = \color{blue}{-2x} -6 $$ |