Question
Answer
$$(x-2y-1)^2=x^2-4xy+4y^2-2x+4y+1$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x-2y-1)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^2-4xy+4y^2-2x+4y+1\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x-2y-1}\right) $ by each term in $ \left( x-2y-1\right) $. $$ \left( \color{blue}{x-2y-1}\right) \cdot \left( x-2y-1\right) = x^2-2xy-x-2xy+4y^2+2y-x+2y+1 $$ |
| ② | Combine like terms: $$ x^2 \color{blue}{-2xy} \color{red}{-x} \color{blue}{-2xy} +4y^2+ \color{green}{2y} \color{red}{-x} + \color{green}{2y} +1 = x^2 \color{blue}{-4xy} +4y^2 \color{red}{-2x} + \color{green}{4y} +1 $$ |
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