Question
Answer
$$(x-2)(x+5)=x^2+3x-10$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x-2)(x+5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^2+5x-2x-10 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^2+3x-10\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x-2}\right) $ by each term in $ \left( x+5\right) $. $$ \left( \color{blue}{x-2}\right) \cdot \left( x+5\right) = x^2+5x-2x-10 $$ |
| ② | Combine like terms: $$ x^2+ \color{blue}{5x} \color{blue}{-2x} -10 = x^2+ \color{blue}{3x} -10 $$ |
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