Question
Answer
$$(x-2)(x^2+8x-1)=x^3+6x^2-17x+2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x-2)(x^2+8x-1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^3+8x^2-x-2x^2-16x+2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^3+6x^2-17x+2\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x-2}\right) $ by each term in $ \left( x^2+8x-1\right) $. $$ \left( \color{blue}{x-2}\right) \cdot \left( x^2+8x-1\right) = x^3+8x^2-x-2x^2-16x+2 $$ |
| ② | Combine like terms: $$ x^3+ \color{blue}{8x^2} \color{red}{-x} \color{blue}{-2x^2} \color{red}{-16x} +2 = x^3+ \color{blue}{6x^2} \color{red}{-17x} +2 $$ |
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