Question
Answer
$$(x-2)(x^2+4)(x-4-6^{1/2})(x-4+6^{1/2})=(x^3+4x-2x^2-8)(x-4-6^{1/2})(x-4+6^{1/2})$$
Explanation
| $$ \begin{aligned}(x-2)(x^2+4)(x-4-6^{1/2})(x-4+6^{1/2})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(x^3+4x-2x^2-8)(x-4-6^{1/2})(x-4+6^{1/2})\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x-2}\right) $ by each term in $ \left( x^2+4\right) $. $$ \left( \color{blue}{x-2}\right) \cdot \left( x^2+4\right) = x^3+4x-2x^2-8 $$ |
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