Question
Answer
$$(x-1)(x^2-8x-3)=x^3-9x^2+5x+3$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x-1)(x^2-8x-3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^3-8x^2-3x-x^2+8x+3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^3-9x^2+5x+3\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x-1}\right) $ by each term in $ \left( x^2-8x-3\right) $. $$ \left( \color{blue}{x-1}\right) \cdot \left( x^2-8x-3\right) = x^3-8x^2-3x-x^2+8x+3 $$ |
| ② | Combine like terms: $$ x^3 \color{blue}{-8x^2} \color{red}{-3x} \color{blue}{-x^2} + \color{red}{8x} +3 = x^3 \color{blue}{-9x^2} + \color{red}{5x} +3 $$ |
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