Question
Answer
$$(x-1)(6x-7)=6x^2-13x+7$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x-1)(6x-7)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6x^2-7x-6x+7 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}6x^2-13x+7\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x-1}\right) $ by each term in $ \left( 6x-7\right) $. $$ \left( \color{blue}{x-1}\right) \cdot \left( 6x-7\right) = 6x^2-7x-6x+7 $$ |
| ② | Combine like terms: $$ 6x^2 \color{blue}{-7x} \color{blue}{-6x} +7 = 6x^2 \color{blue}{-13x} +7 $$ |
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