Question
Answer
$$(x^3+3x^2-9x+5)(x-5)=x^4-2x^3-24x^2+50x-25$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x^3+3x^2-9x+5)(x-5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^4-2x^3-24x^2+50x-25\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x^3+3x^2-9x+5}\right) $ by each term in $ \left( x-5\right) $. $$ \left( \color{blue}{x^3+3x^2-9x+5}\right) \cdot \left( x-5\right) = x^4-5x^3+3x^3-15x^2-9x^2+45x+5x-25 $$ |
| ② | Combine like terms: $$ x^4 \color{blue}{-5x^3} + \color{blue}{3x^3} \color{red}{-15x^2} \color{red}{-9x^2} + \color{green}{45x} + \color{green}{5x} -25 = x^4 \color{blue}{-2x^3} \color{red}{-24x^2} + \color{green}{50x} -25 $$ |
This page was created using
Simplify polynomials calculator