Question
Answer
$$(x^3+2)(x^2+4)=x^5+4x^3+2x^2+8$$
Explanation
| $$ \begin{aligned}(x^3+2)(x^2+4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^5+4x^3+2x^2+8\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x^3+2}\right) $ by each term in $ \left( x^2+4\right) $. $$ \left( \color{blue}{x^3+2}\right) \cdot \left( x^2+4\right) = x^5+4x^3+2x^2+8 $$ |
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