Question
Answer
$$x^3-x^2y-(xy^2+y^3)+x^2y+xy^2=x^3-y^3$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}x^3-x^2y-(xy^2+y^3)+x^2y+xy^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^3-x^2y-xy^2-y^3+x^2y+xy^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^3-y^3\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( xy^2+y^3 \right) = -xy^2-y^3 $$ |
| ② | Combine like terms: $$ x^3 \, \color{blue}{ -\cancel{x^2y}} \, \, \color{green}{ -\cancel{xy^2}} \,-y^3+ \, \color{blue}{ \cancel{x^2y}} \,+ \, \color{green}{ \cancel{xy^2}} \, = x^3-y^3 $$ |
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