Question
Answer
$$(x^3-3x)^2=x^6-6x^4+9x^2$$
Explanation
| $$ \begin{aligned}(x^3-3x)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^6-6x^4+9x^2\end{aligned} $$ | |
| ① | Find $ \left(x^3-3x\right)^2 $ using formula. $$ (A - B)^2 = \color{blue}{A^2} - 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ x^3 } $ and $ B = \color{red}{ 3x }$. $$ \begin{aligned}\left(x^3-3x\right)^2 = \color{blue}{\left( x^3 \right)^2} -2 \cdot x^3 \cdot 3x + \color{red}{\left( 3x \right)^2} = x^6-6x^4+9x^2\end{aligned} $$ |
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