Question
Answer
$$(x^2-8)(2x-4)=2x^3-4x^2-16x+32$$
Explanation
| $$ \begin{aligned}(x^2-8)(2x-4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x^3-4x^2-16x+32\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x^2-8}\right) $ by each term in $ \left( 2x-4\right) $. $$ \left( \color{blue}{x^2-8}\right) \cdot \left( 2x-4\right) = 2x^3-4x^2-16x+32 $$ |
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