Question
Answer
$$(x^2-7)(12x^3-6)=12x^5-84x^3-6x^2+42$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x^2-7)(12x^3-6)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}12x^5-6x^2-84x^3+42 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}12x^5-84x^3-6x^2+42\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x^2-7}\right) $ by each term in $ \left( 12x^3-6\right) $. $$ \left( \color{blue}{x^2-7}\right) \cdot \left( 12x^3-6\right) = 12x^5-6x^2-84x^3+42 $$ |
| ② | Combine like terms: $$ 12x^5-84x^3-6x^2+42 = 12x^5-84x^3-6x^2+42 $$ |
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