Question
Answer
$$(x^2-3)(x+4)=x^3+4x^2-3x-12$$
Explanation
| $$ \begin{aligned}(x^2-3)(x+4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^3+4x^2-3x-12\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x^2-3}\right) $ by each term in $ \left( x+4\right) $. $$ \left( \color{blue}{x^2-3}\right) \cdot \left( x+4\right) = x^3+4x^2-3x-12 $$ |
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