Question
Answer
$$(x^2-1)(x^2-4)=x^4-5x^2+4$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x^2-1)(x^2-4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^4-4x^2-x^2+4 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^4-5x^2+4\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x^2-1}\right) $ by each term in $ \left( x^2-4\right) $. $$ \left( \color{blue}{x^2-1}\right) \cdot \left( x^2-4\right) = x^4-4x^2-x^2+4 $$ |
| ② | Combine like terms: $$ x^4 \color{blue}{-4x^2} \color{blue}{-x^2} +4 = x^4 \color{blue}{-5x^2} +4 $$ |
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