Question
Answer
$$x\cdot(1-x)+0=-x^2+x$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}x\cdot(1-x)+0& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x-x^2+0 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-x^2+x\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{x} $ by $ \left( 1-x\right) $ $$ \color{blue}{x} \cdot \left( 1-x\right) = x-x^2 $$ |
| ② | Combine like terms: $$ -x^2+x = -x^2+x $$ |
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