Question
Answer
$$(s^2-4s-1)(-3s^2+4s-2)=-3s^4+16s^3-15s^2+4s+2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(s^2-4s-1)(-3s^2+4s-2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-3s^4+16s^3-15s^2+4s+2\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{s^2-4s-1}\right) $ by each term in $ \left( -3s^2+4s-2\right) $. $$ \left( \color{blue}{s^2-4s-1}\right) \cdot \left( -3s^2+4s-2\right) = -3s^4+4s^3-2s^2+12s^3-16s^2+8s+3s^2-4s+2 $$ |
| ② | Combine like terms: $$ -3s^4+ \color{blue}{4s^3} \color{red}{-2s^2} + \color{blue}{12s^3} \color{green}{-16s^2} + \color{orange}{8s} + \color{green}{3s^2} \color{orange}{-4s} +2 = \\ = -3s^4+ \color{blue}{16s^3} \color{green}{-15s^2} + \color{orange}{4s} +2 $$ |
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