Question
Answer
$$(n+3)^2n=n^3+6n^2+9n$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(n+3)^2n& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(1n^2+6n+9)n \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}n^3+6n^2+9n\end{aligned} $$ | |
| ① | Find $ \left(n+3\right)^2 $ using formula. $$ (A + B)^2 = \color{blue}{A^2} + 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ n } $ and $ B = \color{red}{ 3 }$. $$ \begin{aligned}\left(n+3\right)^2 = \color{blue}{n^2} +2 \cdot n \cdot 3 + \color{red}{3^2} = n^2+6n+9\end{aligned} $$ |
| ② | $$ \left( \color{blue}{n^2+6n+9}\right) \cdot n = n^3+6n^2+9n $$ |
This page was created using
Simplify polynomials calculator