Question
Answer
$$(mx+2)(3x-5)=3mx^2-5mx+6x-10$$
Explanation
| $$ \begin{aligned}(mx+2)(3x-5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3mx^2-5mx+6x-10\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{mx+2}\right) $ by each term in $ \left( 3x-5\right) $. $$ \left( \color{blue}{mx+2}\right) \cdot \left( 3x-5\right) = 3mx^2-5mx+6x-10 $$ |
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