Question
Answer
$$(m-4)^3=m^3-12m^2+48m-64$$
Explanation
| $$ \begin{aligned}(m-4)^3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}m^3-12m^2+48m-64\end{aligned} $$ | |
| ① | Find $ \left(m-4\right)^3 $ using formula $$ (A - B) = A^3 - 3A^2B + 3AB^2 - B^3 $$where $ A = m $ and $ B = 4 $. $$ \left(m-4\right)^3 = m^3-3 \cdot m^2 \cdot 4 + 3 \cdot m \cdot 4^2-4^3 = m^3-12m^2+48m-64 $$ |
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