Question
Answer
$$(k+1)^3=k^3+3k^2+3k+1$$
Explanation
| $$ \begin{aligned}(k+1)^3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}k^3+3k^2+3k+1\end{aligned} $$ | |
| ① | Find $ \left(k+1\right)^3 $ using formula $$ (A + B) = A^3 + 3A^2B + 3AB^2 + B^3 $$where $ A = k $ and $ B = 1 $. $$ \left(k+1\right)^3 = k^3+3 \cdot k^2 \cdot 1 + 3 \cdot k \cdot 1^2+1^3 = k^3+3k^2+3k+1 $$ |
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