Question
Answer
$$(j+5)(j-9)=j^2-4j-45$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(j+5)(j-9)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}j^2-9j+5j-45 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}j^2-4j-45\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{j+5}\right) $ by each term in $ \left( j-9\right) $. $$ \left( \color{blue}{j+5}\right) \cdot \left( j-9\right) = j^2-9j+5j-45 $$ |
| ② | Combine like terms: $$ j^2 \color{blue}{-9j} + \color{blue}{5j} -45 = j^2 \color{blue}{-4j} -45 $$ |
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