Question
Answer
$$(h-6)(h-3)=h^2-9h+18$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(h-6)(h-3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}h^2-3h-6h+18 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}h^2-9h+18\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{h-6}\right) $ by each term in $ \left( h-3\right) $. $$ \left( \color{blue}{h-6}\right) \cdot \left( h-3\right) = h^2-3h-6h+18 $$ |
| ② | Combine like terms: $$ h^2 \color{blue}{-3h} \color{blue}{-6h} +18 = h^2 \color{blue}{-9h} +18 $$ |
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