Question
Answer
$$f^3-5f+25-(4f^2-12f+9)=f^3-4f^2+7f+16$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}f^3-5f+25-(4f^2-12f+9)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}f^3-5f+25-4f^2+12f-9 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}f^3-4f^2+7f+16\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 4f^2-12f+9 \right) = -4f^2+12f-9 $$ |
| ② | Combine like terms: $$ f^3 \color{blue}{-5f} + \color{red}{25} -4f^2+ \color{blue}{12f} \color{red}{-9} = f^3-4f^2+ \color{blue}{7f} + \color{red}{16} $$ |
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