| $$ \begin{aligned}(e+6)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}e^2+12e+36\end{aligned} $$ | |
| ① | Find $ \left(e+6\right)^2 $ using formula. $$ (A + B)^2 = \color{blue}{A^2} + 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ e } $ and $ B = \color{red}{ 6 }$. $$ \begin{aligned}\left(e+6\right)^2 = \color{blue}{e^2} +2 \cdot e \cdot 6 + \color{red}{6^2} = e^2+12e+36\end{aligned} $$ |