| $$ \begin{aligned}(a+x)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}a^2+2ax+x^2\end{aligned} $$ | |
| ① | Find $ \left(a+x\right)^2 $ using formula. $$ (A + B)^2 = \color{blue}{A^2} + 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ a } $ and $ B = \color{red}{ x }$. $$ \begin{aligned}\left(a+x\right)^2 = \color{blue}{a^2} +2 \cdot a \cdot x + \color{red}{x^2} = a^2+2ax+x^2\end{aligned} $$ |