Question
Answer
$$(a-3)(a+8)=a^2+5a-24$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(a-3)(a+8)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}a^2+8a-3a-24 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}a^2+5a-24\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{a-3}\right) $ by each term in $ \left( a+8\right) $. $$ \left( \color{blue}{a-3}\right) \cdot \left( a+8\right) = a^2+8a-3a-24 $$ |
| ② | Combine like terms: $$ a^2+ \color{blue}{8a} \color{blue}{-3a} -24 = a^2+ \color{blue}{5a} -24 $$ |
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