Question
Answer
$$9y^2+6y-2-(-3y+9)=9y^2+9y-11$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}9y^2+6y-2-(-3y+9)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}9y^2+6y-2+3y-9 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}9y^2+9y-11\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( -3y+9 \right) = 3y-9 $$ |
| ② | Combine like terms: $$ 9y^2+ \color{blue}{6y} \color{red}{-2} + \color{blue}{3y} \color{red}{-9} = 9y^2+ \color{blue}{9y} \color{red}{-11} $$ |
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