Question
Answer
$$(9x-6)(9x+6)=81x^2-36$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(9x-6)(9x+6)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}81x^2+54x-54x-36 \xlongequal{ } \\[1 em] & \xlongequal{ }81x^2+ \cancel{54x} -\cancel{54x}-36 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}81x^2-36\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{9x-6}\right) $ by each term in $ \left( 9x+6\right) $. $$ \left( \color{blue}{9x-6}\right) \cdot \left( 9x+6\right) = 81x^2+ \cancel{54x} -\cancel{54x}-36 $$ |
| ② | Combine like terms: $$ 81x^2+ \, \color{blue}{ \cancel{54x}} \, \, \color{blue}{ -\cancel{54x}} \,-36 = 81x^2-36 $$ |
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