Question
Answer
$$(9x-1)(3x+1)=27x^2+6x-1$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(9x-1)(3x+1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}27x^2+9x-3x-1 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}27x^2+6x-1\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{9x-1}\right) $ by each term in $ \left( 3x+1\right) $. $$ \left( \color{blue}{9x-1}\right) \cdot \left( 3x+1\right) = 27x^2+9x-3x-1 $$ |
| ② | Combine like terms: $$ 27x^2+ \color{blue}{9x} \color{blue}{-3x} -1 = 27x^2+ \color{blue}{6x} -1 $$ |
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