Tap the blue circles to see an explanation.
| $$ \begin{aligned}(9x^2+8)(8x+7+\frac{4}{x})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(9x^2+8)\frac{8x^2+7x+4}{x} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{72x^4+63x^3+100x^2+56x+32}{x}\end{aligned} $$ | |
| ① | Add $8x+7$ and $ \dfrac{4}{x} $ to get $ \dfrac{ \color{purple}{ 8x^2+7x+4 } }{ x }$. Step 1: Write $ 8x+7 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To add raitonal expressions, both fractions must have the same denominator. |
| ② | Multiply $9x^2+8$ by $ \dfrac{8x^2+7x+4}{x} $ to get $ \dfrac{72x^4+63x^3+100x^2+56x+32}{x} $. Step 1: Write $ 9x^2+8 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 9x^2+8 \cdot \frac{8x^2+7x+4}{x} & \xlongequal{\text{Step 1}} \frac{9x^2+8}{\color{red}{1}} \cdot \frac{8x^2+7x+4}{x} \xlongequal{\text{Step 2}} \frac{ \left( 9x^2+8 \right) \cdot \left( 8x^2+7x+4 \right) }{ 1 \cdot x } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 72x^4+63x^3+36x^2+64x^2+56x+32 }{ x } = \frac{72x^4+63x^3+100x^2+56x+32}{x} \end{aligned} $$ |