Question
Answer
$$9x^2-4x-(5x^2-3x)=4x^2-x$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}9x^2-4x-(5x^2-3x)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}9x^2-4x-5x^2+3x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4x^2-x\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 5x^2-3x \right) = -5x^2+3x $$ |
| ② | Combine like terms: $$ \color{blue}{9x^2} \color{red}{-4x} \color{blue}{-5x^2} + \color{red}{3x} = \color{blue}{4x^2} \color{red}{-x} $$ |
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