Question
Answer
$$(9x^2-4)(2x^2-8x+4)=18x^4-72x^3+28x^2+32x-16$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(9x^2-4)(2x^2-8x+4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}18x^4-72x^3+36x^2-8x^2+32x-16 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}18x^4-72x^3+28x^2+32x-16\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{9x^2-4}\right) $ by each term in $ \left( 2x^2-8x+4\right) $. $$ \left( \color{blue}{9x^2-4}\right) \cdot \left( 2x^2-8x+4\right) = 18x^4-72x^3+36x^2-8x^2+32x-16 $$ |
| ② | Combine like terms: $$ 18x^4-72x^3+ \color{blue}{36x^2} \color{blue}{-8x^2} +32x-16 = 18x^4-72x^3+ \color{blue}{28x^2} +32x-16 $$ |
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