Question
Answer
$$(9r+5)^2=81r^2+90r+25$$
Explanation
| $$ \begin{aligned}(9r+5)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}81r^2+90r+25\end{aligned} $$ | |
| ① | Find $ \left(9r+5\right)^2 $ using formula. $$ (A + B)^2 = \color{blue}{A^2} + 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ 9r } $ and $ B = \color{red}{ 5 }$. $$ \begin{aligned}\left(9r+5\right)^2 = \color{blue}{\left( 9r \right)^2} +2 \cdot 9r \cdot 5 + \color{red}{5^2} = 81r^2+90r+25\end{aligned} $$ |
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