Question
Answer
$$(9q-5)(4q-7)=36q^2-83q+35$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(9q-5)(4q-7)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}36q^2-63q-20q+35 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}36q^2-83q+35\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{9q-5}\right) $ by each term in $ \left( 4q-7\right) $. $$ \left( \color{blue}{9q-5}\right) \cdot \left( 4q-7\right) = 36q^2-63q-20q+35 $$ |
| ② | Combine like terms: $$ 36q^2 \color{blue}{-63q} \color{blue}{-20q} +35 = 36q^2 \color{blue}{-83q} +35 $$ |
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