Question
Answer
$$8x^2-4x+6-(5x^2+4x-7)=3x^2-8x+13$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}8x^2-4x+6-(5x^2+4x-7)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}8x^2-4x+6-5x^2-4x+7 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}3x^2-8x+13\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 5x^2+4x-7 \right) = -5x^2-4x+7 $$ |
| ② | Combine like terms: $$ \color{blue}{8x^2} \color{red}{-4x} + \color{green}{6} \color{blue}{-5x^2} \color{red}{-4x} + \color{green}{7} = \color{blue}{3x^2} \color{red}{-8x} + \color{green}{13} $$ |
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