| $$ \begin{aligned}(7y+2)^3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}343y^3+294y^2+84y+8\end{aligned} $$ | |
| ① | Find $ \left(7y+2\right)^3 $ using formula $$ (A + B) = A^3 + 3A^2B + 3AB^2 + B^3 $$where $ A = 7y $ and $ B = 2 $. $$ \left(7y+2\right)^3 = \left( 7y \right)^3+3 \cdot \left( 7y \right)^2 \cdot 2 + 3 \cdot 7y \cdot 2^2+2^3 = 343y^3+294y^2+84y+8 $$ |