Question
Answer
$$(7y-2)(y+5)=7y^2+33y-10$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(7y-2)(y+5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}7y^2+35y-2y-10 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}7y^2+33y-10\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{7y-2}\right) $ by each term in $ \left( y+5\right) $. $$ \left( \color{blue}{7y-2}\right) \cdot \left( y+5\right) = 7y^2+35y-2y-10 $$ |
| ② | Combine like terms: $$ 7y^2+ \color{blue}{35y} \color{blue}{-2y} -10 = 7y^2+ \color{blue}{33y} -10 $$ |
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