Question
Answer
$$(7x-8)(5x-1)=35x^2-47x+8$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(7x-8)(5x-1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}35x^2-7x-40x+8 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}35x^2-47x+8\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{7x-8}\right) $ by each term in $ \left( 5x-1\right) $. $$ \left( \color{blue}{7x-8}\right) \cdot \left( 5x-1\right) = 35x^2-7x-40x+8 $$ |
| ② | Combine like terms: $$ 35x^2 \color{blue}{-7x} \color{blue}{-40x} +8 = 35x^2 \color{blue}{-47x} +8 $$ |
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