Question
Answer
$$(7x-2)(4x-3)=28x^2-29x+6$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(7x-2)(4x-3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}28x^2-21x-8x+6 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}28x^2-29x+6\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{7x-2}\right) $ by each term in $ \left( 4x-3\right) $. $$ \left( \color{blue}{7x-2}\right) \cdot \left( 4x-3\right) = 28x^2-21x-8x+6 $$ |
| ② | Combine like terms: $$ 28x^2 \color{blue}{-21x} \color{blue}{-8x} +6 = 28x^2 \color{blue}{-29x} +6 $$ |
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