Question
Answer
$$7x^3+2x^2-x-4-(4x^2+8)=7x^3-2x^2-x-12$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}7x^3+2x^2-x-4-(4x^2+8)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}7x^3+2x^2-x-4-4x^2-8 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}7x^3-2x^2-x-12\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 4x^2+8 \right) = -4x^2-8 $$ |
| ② | Combine like terms: $$ 7x^3+ \color{blue}{2x^2} -x \color{red}{-4} \color{blue}{-4x^2} \color{red}{-8} = 7x^3 \color{blue}{-2x^2} -x \color{red}{-12} $$ |
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