Question
Answer
$$(7x^2+dx+t)^2=d^2x^2+14dx^3+49x^4+2dtx+14tx^2+t^2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(7x^2+dx+t)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}d^2x^2+14dx^3+49x^4+2dtx+14tx^2+t^2\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{7x^2+dx+t}\right) $ by each term in $ \left( 7x^2+dx+t\right) $. $$ \left( \color{blue}{7x^2+dx+t}\right) \cdot \left( 7x^2+dx+t\right) = 49x^4+7dx^3+7tx^2+7dx^3+d^2x^2+dtx+7tx^2+dtx+t^2 $$ |
| ② | Combine like terms: $$ 49x^4+ \color{blue}{7dx^3} + \color{red}{7tx^2} + \color{blue}{7dx^3} +d^2x^2+ \color{green}{dtx} + \color{red}{7tx^2} + \color{green}{dtx} +t^2 = \\ = d^2x^2+ \color{blue}{14dx^3} +49x^4+ \color{green}{2dtx} + \color{red}{14tx^2} +t^2 $$ |
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